Plimmerton School

Stage Emergent

I am learning to count forwards and backwards to 10

Counting Song 1-10 

Counting back from 10

Stage One: One-to-One Counting 

I am able to count or make a set of objects.

One to one counting

Learn to Count: Counting Using One to One Correspondence

Teaching the One-to-One Counting Principle

Stage Two: Counting from One on Materials 

I am able to solve simple addition and subtraction problems by counting all the objects, using materials.

Example: 5 + 4 as 1,2,3,4,5,6,7,8,9.

Addition - counting all from one

I am able to solve multiplication and division problems by counting one-to-one with the help of materials.

Example: 2 x 6 as 1,2,3,4,5,6,7,8,9,10,11,12

Multiplication by counting objects - skip counting

I am able to divide a set of objects into equal groups or a shape into equal parts using materials.

How to Share Equally - Introduction to Division.

Wholes, Quarters and halves

Stage Three: Counting from One by Imaging  

I am able to count all of the objects in simple addition, subtraction and multiplication problems in my head.

Example: “8 + 5 as, I counted in my head like this: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13”.

Example: “4 x 2 = I counted in my head like this 1, 2, 3, 4, 5, 6, 7, 8”

Stage 4: Advanced Counting (Counting On) 

I am able to count on from the biggest number to solve addition problems. 

Example: “8 + 5 = I thought of 8, and then 9, 10, 11, 12, 13”

Counting on from the biggest number

Counting On Song

Adding to 20 (Counting On)

I am able to count back from the biggest number to solve subtraction problems

Example: 52 - 4 is  “I thought of 52, and then 51, 50, 49, 48

Subtraction by counting back 

I am able to solve addition and subtraction problems by counting in 10’s. Example: “13 + 40 is, I thought of 13 in my head, and counted 23, 33, 43, 53”

Counting in tens 

I am able to skip count to solve simple multiplication problems.

Example: “4 x 5 = 5, 10, 15, 20”

Solve multiplication problems using skip counting

Skip counting to solve multiplication and division

I am able to divide a set of objects into equal groups or a shape into equal parts with or without materials.

Example: “½ of 8”

Addition and Subtraction

I am able to use known basic facts to solve addition and subtraction problems.

I am able to use doubles. 

Example: 8 + 7 is 8 + 8 - 1 

Using Doubles to solve addition

I am able to solve multi-digit problems using partitioning. 

Example: 43 + 25 = (40 + 20) + (3 + 5) = 60 + 8 = 68

Partitioning with Addition

I am able to use rounding and compensating. 

Example: 39 + 26 = 40 + 25 = 65

Rounding and Compensating with Addition

I am able to solve subtraction problems by partitioning the second number. 

Example: 84 - 8 is 84 - 4 - 4 = 76

Multiplication and Division

I am able to solve multiplication and division problems by using repeated addition. 

Example 1: 4 x 6 as (6 + 6) + (6 + 6) = 12 + 12 = 24

Example 2: 20 ➗ 4 = 5 because 5 + 5 = 10 and 10 + 10 = 20.

Repeated Addition for Multiplication

Fractions

I am able to find a fraction of a number.

Example: ⅓ of 12 = 4 because 4 + 4 + 4 = 12

Find a fraction of a set

Addition and Subtraction

I am able to use a range of the following strategies to solve problems;

I am able to use rounding and compensating 

Example: 63 - 39 = 63 - 40 + 1 = 24

Compensating and Rounding Addition

Compensating and Rounding Subtraction

I am able to use reversibility (number line)

Example: 63 - 39 = 39 + ▢ = 63

Reversibility and Compensating

Number Line

I am able to use place value partitioning

Example: 156 - 38 = (156 - 30 = 126) 126 - 8 = 118

Addition Partitioning

Subtraction Partitioning

Multiplication and Division

I am able to use doubling and halving

Example: 4 x 8 = 2 x 16 - 32

Doubling and Halving

I am able to solve unknown facts from facts I know

Example: 9 x 6 is (10 x 6) - 6 = 54

I am able to reverse division problems into multiplication problems

Example: 63 ➗ 7 = 9 because 9 x 7 = 63 (reversibility)

Fractions

I am able to find a fraction of a set by using multiplication or division facts.

Example: ⅓ of 36 = 12 because 36 ➗ 3 = 12, or 3 x 12 = 36

Finding Fraction of a set

I am able to rename improper fractions

11/3 = 3 3/11 because 3 fits into 11 3 times with a remainder of 3.

Improper to mixed fractions

Addition and Subtraction

I am able to solve addition and subtraction problems with decimals up to 2 decimal places using; 

• Rounding and Compensating 

• Reversibility (number line) 

• Place Value Partitioning

I am able to solve problems for integers

Integers Video

Multiplication and Division

I am able to multiply 2 digit by 1 digit numbers 

Box method for 2 digit by 1 digit

I am able to multiply 2 digit by 2 digit numbers

Box method for 2 digit by 2 digit 

I am able to solve division problems using;

• Proportional Adjustment

• Rounding and Divisibility / Doubling and Halving / Place value partitioning

Fractions

I am able to find equivalent fractions

Equivalent Fractions

I am able to find the decimals and percentages of a fraction

Decimals, Fractions and Percentages 

I am able to find fractions of a set

Find fractions of a set

I am able to solve simple ratio problems

Finding a Whole

Finding a whole